将“χ的16次方+x的8次方+1“因式分解

x^16+x^8+1=(x^8)^2+2x^8+1-x^8=(x^8+1)^2-(x^4)^2=(x^8+1+x^4)(x^8+1-x^4)=[(x^4)^2+2x^4+1-x^4](x^8-x^4+1)=[(x^4+1)^2-(x^2)^2](x^8-x^4+1)=(x^4+1+x^2)(x^4+1-x^2)(x^8-x^4+1)=[(x^2)^2+2x^2+1-x^2)(x^4-x^2+1)(...