=lim(h→0)(f(x0+h) - f(x0) + f(x0) -f(x0-h))/2h
=(1/2)lim(h→0)(f(x0+h) - f(x0) )/h + (1/2)lim(h→0)(f(x0-h) - f(x0) )/(-h)
=(1/2)f'(x0) + (1/2)f'(x0)
= f'(x0)
设函数f(x)在点x0处可导,求lim(h→0)(f(x0+h)-f(x0-h))/2h的值
设函数f(x)在点x0处可导,求lim(h→0)(f(x0+h)-f(x0-h))/2h的值
数学人气:218 ℃时间:2019-08-16 22:43:48
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