已知a+b+c=0,a+2b+3c=0,且abc不等于0,求(ab+bc+ca)/b^2的值

abc不等于0,即 A,B,C都不等于0
a+b+c=0,(1)
a+2b+3c=0 (2)
(2)-(1):B+2C=0 ==>B=-2C ,A=C
所以(ab+bc+ca)/b^2=(C*(-2C)+(-2C)*C+C*C)/(-2C)^2=-3C^2/(4C^2)=-3/4