由a>2得
loga(a+1)>0,loga(a-1)>0
由当a=b,a>0,b>0时,a*b<(a^2+b^2)/2 得
loga(a+1)*loga(a-1)
<[loga(a+1)+loga(a-1)]^2/4
=[loga(a^2-1)]^2/4
<[loga(a^2)]^2/4
=2^2/4
=1
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