∵(3x-y)²≥0,|2x-y-3|≥0
且(3x-y)²+|2x-y-3|=0
∴3x-y=0,2x-y-3=0
解得x=-3,y=-9
原式=10x-5y-12x+4y-4+4x-3y-1/2
=2x-4y-9/2
当x=-3,y=-9时
原式=2×(-3)-4×(-9)-9/2=51/2
以上为这种类型题目的标准答题过程,一定要掌握的~若不懂,
已知(3x-y)^2+|2x-y-3|=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-二分之一)
已知(3x-y)^2+|2x-y-3|=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-二分之一)
数学人气:128 ℃时间:2019-08-21 22:32:16
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