3x²-2(mx-1)²
3x²-2(m²x²-2mx+1)
3x²-2m²x²+4mx-2
(3-2m²)x²+4mx-2
互为相反数的两个数相加等于零
3-2m²-2=0
1-2m²=0
m²=1/2
m=±(√2)/2
若二次函数y=3x²-2(mx-1)²的二次项系数与常数项互为相反数,求m的值
若二次函数y=3x²-2(mx-1)²的二次项系数与常数项互为相反数,求m的值
数学人气:964 ℃时间:2020-03-30 16:10:00
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