二重积分 由柱面x^2+y^2=y和平面z=0,6x+4y+z=12所围立体体积
二重积分 由柱面x^2+y^2=y和平面z=0,6x+4y+z=12所围立体体积
数学人气：180 ℃时间：2019-10-19 19:30:31
优质解答
积分区域是圆：x²+y²=y,参数方程 x=(cost)/2,y=(1+sint)/2；被积函数是 (12-6x-4y-0)；V=∫∫∫dxdydz=∫∫[12-6x-4y]dxdy=∫(12-3cost-2-2sint)[(1/2)² dt]……t=0→2π=(1/4)∫(10-3cost-2sint)dt=...答案不应该是5Π/2?��Ӧ����5��/2��ǰ��ڶ���������������dxdyӦ��Ϊ��(1/2)(1/2)² dt����
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