(y+1)平方-2x平方(1+y平方)+x四次方(1-y)平方

(y+1)平方-2x平方(1+y平方)+x四次方(1-y)平方=(y+1)²+2*x²*(y²-1)+[x²(y-1)]²-2x²(y²+1+y²-1)=[(y+1)+x(y-1)]²-(2xy)²=(xy-x+y+1+2xy)(xy-x+y+1-2xy)=(3xy-x+y+1...你好象 错的吧~是呀，错了(y+1)平方-2x平方(1+y平方)+x四次方(1-y)平方=(y+1)²+2x²*(y+1)(y-1)+(x²)²(y-1)²-2x²(y+1)(y-1)-2x²(y²+1)=(y+1)²+2*x²*(y²-1)+[x²(y-1)]²-2x²(y²-1+y²+1)=(x²y-x²+y+1)²-(2xy)²=(x²y+2xy-x²+y+1)(x²y-2xy-x²+y+1)=[y(x+1)²-(x+1)(x-1)]*[y(x-1)²-(x+1)(x-1)]=(x+1)(xy+y-x+1)(x-1)(xy-y-x-1)