当m为何值时,去分母,解方程4x+1/3x-6=1-(5x-m/2-x)会产生增根

(4x+1)/(3x-6)=1-(5x-m)/(2-x)——》(4x+1)/3(x-2)+3(m-5x)/3(x-2)-1=0——》(7+3m-14x)/3(x-2)=0,去分母时,x-2≠0,即：x≠2,7+3m-14x=0——》x=(7+3m)/14≠2——》m≠7,即：当m=7时,去分母会产生增根x=2....