在三角形ABC中,若cos2A+cos2B+cos2C=-1,试判断三角形ABC的形状?
在三角形ABC中,若cos2A+cos2B+cos2C=-1,试判断三角形ABC的形状?
数学人气:336 ℃时间:2019-10-19 21:35:02
优质解答
由正弦定理得a/sinA=b/sinB,因为acosA=bcosB,所以sinAcosB-cosAsinB=sin(A-B)=0,所以∠A=∠B.cos2A+cos2B-cos2C=2cos2A-cos2C=2cos2A-cos2(180-A-B)=2cos2A-cos2(180-2A)=2cos2A-cos(360-4A)=2cos2A-cos4A=2...不活,题目是 在三角形ABC中,若cos2A+cos2B+cos2C=-1,试判断三角形ABC的形状?看清给可以,老大,但也给我了提示,我做出来了!哦
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