解分式方程: (1)2/x+1+3/x−1=6/x2−1 (2)x−3x−2+1=3/2−x.
解分式方程:
(1)
+
=
(2)
+1=
.
(1)
2 |
x+1 |
3 |
x−1 |
6 |
x2−1 |
(2)
x−3 |
x−2 |
3 |
2−x |
数学人气:985 ℃时间:2020-01-28 00:47:52
优质解答
(1)2x+1+3x−1=6x2−1(x+1)(x-1)(2x+1+3x−1)=6(x−1)(x+1)×(x+1)(x-1),∴2(x-1)+3(x+1)=6,5x=5,解得:x=1,检验:当x=1时,(x+1)(x-1)=0,∴x=1不是原方程的解.∴原方程无解;(2)x−3x...
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