x³的系数为:-3+2a=5
x²的系数为:1-3a-2b=6
所以
a=4
2b=1-3a-6=1-12-6=-17
b=-17/2
若(x²+ax-b)(2x²-3x+1)的积中,x³的系数为5,x²的系数为6,求a,b.
若(x²+ax-b)(2x²-3x+1)的积中,x³的系数为5,x²的系数为6,求a,b.
数学人气:553 ℃时间:2019-12-06 20:21:45
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