(x的平方+xy+y的平方)(x的平方+xy+3y的平方)+y的四次方
(x的平方+xy+y的平方)(x的平方+xy+3y的平方)+y的四次方
数学人气：197 ℃时间：2019-10-17 03:13:32
优质解答
原式=[(x²+xy)+y²][(x²+xy)+3y²]+y^4=(x²+xy)²+4(x²+xy)y²+3y^4+y^4=(x²+xy)²+4(x²+xy)y²+4y^4=[(x²+xy)+2y²]²=(x²+xy+2y²)...
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