根号3tan(pai/6-θ）tan(pai/6+θ）+tan(pai/6-θ）+tan(pai/6+θ)=?

tan(π/6-θ) =[ tanπ/6-tanθ]/(1+tanπ/6tanθ) = [1/√3 - tanθ]/(1+tanθ/√3)= (1-√3tanθ)/(√3+tanθ)tan(π/6+θ) =(1+√3tanθ)/(√3-tanθ)√3tan(π/6-θ)tan(π/6+θ）+tan(π/6-θ)+tan(π/6+θ)=√...