若x=根号5/2,求根号x+1-根号x-1/根号x+1+根号x-1 + 根号x+1+根号x-1/根号x+1-根号x-1 的值

[√(x+1)-√(x-1)]/[√(x+1)+√(x-1)] + [√(x+1)+√(x-1)]/[√(x+1)-√(x-1)] =[√(x+1)-√(x-1)]^2/[√(x+1)+√(x-1)][√(x+1)-√(x-1)] + [√(x+1)+√(x-1)]^2/[√(x+1)-√(x-1)][√(x+1)+√(x-1)]}=[√(x+1)-√(...