已知有理数a,b,c满足丨a-1丨+丨b+3丨+丨3c-1丨=0求(abc)的2013次方÷(a

因为绝对值大于等于零,所以三个绝对值均为零时结果才能为零
即丨a-1丨=0 丨b+3丨=0 丨3c-1丨=0
解得 a=1 b= -3 c = 1/3
故 a^9 = 1 b^3 = 9 c^2= 1/9
abc = -3 a^9 * b^2 * c^2= 1 *9* 1/9 = 1
故(abc)^2013 /(a^9 * b^2* c^2) = (-3)^2013 /1
= (-3)^2013