y=-x2+2x+3
=-x^2+2x-1+4
=-(x-1)^2+4
x=1时,最大值=4
x=0时,最小值=3
1
如果函数y=-x2+2x+3在闭区间[0,m]上有最大值4,最小值3,求m的取值范围
如果函数y=-x2+2x+3在闭区间[0,m]上有最大值4,最小值3,求m的取值范围
数学人气:136 ℃时间:2019-09-24 05:27:14
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