x-1=0
y+2=0
∴x=1
y=-2
(x+y)^2010=(1-2)^2010=1
(x-1)*(x-1)+(y+2)*(y+2)=0求(x+y)的2010次方
(x-1)*(x-1)+(y+2)*(y+2)=0求(x+y)的2010次方
数学人气:570 ℃时间:2020-02-01 12:30:53
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