大学高数,抛物线y^2=x与直线y=x围成的图形面积用定积分表示为

y=x
y²=x
x²=x
x(x-1)=0
x1=0 x2=1
y=√x
面积：∫（0,1）(√x-x)dx=[x^(3/2)/(3/2)-x²/2] |(0,1)
=1^(3/2)/(3/2)-1²/2-0^(3/2)/(3/2)+0²/2
=2/3-1/2
=4/6-3/6
=1/6填空题应该填什么呢？面积：∫（0,1）(√x-x)dx