定义域(0,+00)
x>0,f'(x)=1/x+2>2
所以函数单调递增.
x趋近于0时候,f(x)趋近于负无穷大
x趋近于正无穷大时候,f(x)趋近于正无穷大
于是,f(x)只有一个零点.
f(1)=0+2-1=1;
f(1/e)=-1+2/e-1=2/e-2
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