如果x四次方+mx三次方+nx-16有因式x²-3x+2,则m于n的值

设 x^4+m*x^3+n*x-16=(x^2-3*x+2)*（x^2+ax+b)所以 x^4+m*x^3+n*x-16=x^4+(a-3)*x^3+(b-3a+2)*x^2+(2a-3b)*x+2b则a-3=mb-3a+2=02a-3b=n2b=-16所以b=-8 b-3a+2=0 a=2 则m=-1 n=26