∵a,b互为倒数,c,d互为相反数
∴ab=1c+d=0
3ab+(2c+3d )\(3c+2d)
=3ab+[2(c+d)+d]/[3(c+d)-d]
=3×1+d/(-d)
=2
若a,b互为倒数,c,d互为相反数,且c,d都不为0,求3ab+(2c+3d )\(3c+2d)的值
若a,b互为倒数,c,d互为相反数,且c,d都不为0,求3ab+(2c+3d )\(3c+2d)的值
数学人气:530 ℃时间:2019-08-24 06:16:18
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