关于x的方程...有唯一解的条件是...

是不是(x+1)/(m+2n)=2m/(m^2-4n^2)-(x-1)/(m-2n)两边乘(m+2n)(m-2n)(m-2n)(x+1)=2m-(m+2n)(x-1)(m-2n+m+2n)x=2m+m+2n-m+2n2mx=2m+4n有唯一解则x系数不等于0所以m≠0且分母不等于0所以m+2n≠0,m-2n≠0综上m≠0且m≠±...