(2003+1/2)-(2002+1/3)+(2001+1/2)-(2000+1/3)……+(1+1/2)-1/3
=(2003-2002)+(2001-2000)+……(1-0)+(1/2-1/3)×1002
=1002+(1/6×1002)
=1002+167
=1169
计算:(2003+1/2)-(2002+1/3)+(2001+1/2)-(2000+1/3)……+(1+1/2)-1/3
计算:(2003+1/2)-(2002+1/3)+(2001+1/2)-(2000+1/3)……+(1+1/2)-1/3
数学人气:777 ℃时间:2019-08-20 03:12:21
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