解
(x-x²-5)-(-2x²+x-3)
=x-x²-5+2x²-x+3
=(2x²-x²)+(x-x)+(3-5)
=x²-2
∵x=2
∴原式
=4-2
=2
当x=2时(x-x的平方-5)-(-2x的平方+x-3)的值为
当x=2时(x-x的平方-5)-(-2x的平方+x-3)的值为
数学人气：285 ℃时间：2020-04-05 21:41:31
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