=(2-3)^2002乘以(根号2+根号3)
=1乘以(根号2+根号3)
=根号2+根号3
用平方差做,(根号2-根号3)^2002与(根号2+根号3)^2002相互抵消,最后只剩根号2+根号3
(根号2-根号3)^2002乘以(根号2+根号3)^2003等于多少?
(根号2-根号3)^2002乘以(根号2+根号3)^2003等于多少?
数学人气：982 ℃时间：2020-04-13 07:30:50
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