已知函数f(x)=2sin(ωx+φ),x∈R(之中A>0,ω>0,0

1、
T=2π/ω=π
ω=2
过M
所以-2=2sin(4π/3+φ)
4π/3+φ=3π/2
φ=π/6
y=2sin(2x+π/6)
2、
0<=x<=π/12
0<=2x<=π/6
π/6<=2x+π/6<=π/3
sinx在(π/6,π/3)是增函数
所以
2x+π/6=π/6,f(x)最小=1/2
2x+π/6=π/3,f(x)最大=√3/2