奇数项:6,8,10,12,(14)
偶数项:3,5,7,9,(11)
所以括号项为14,11.
后面的规律为连续4个自然数的积加1为平方数:
n(n+1)(n+2)(n+3)+1
=(n^2+3n)(n^2+3n+2)+1
=(n^2+3n)^2+2(n^2+3n)+1
=(n^2+3n+1)^2
找规律填空:6、3、8、5、10、7、12、9、( )、( ).还有:仔细观察下面的三个算式,然后小结出一条规律.
找规律填空:6、3、8、5、10、7、12、9、( )、( ).还有:仔细观察下面的三个算式,然后小结出一条规律.
1×2×3×4+1=25(5²)
2×3×4×5+1=121(11²)
3×4×5×6+1=361(19²)
规律:
1×2×3×4+1=25(5²)
2×3×4×5+1=121(11²)
3×4×5×6+1=361(19²)
规律:
数学人气:518 ℃时间:2020-04-23 02:11:08
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