已知sin(X+Y)=2/3,sin(X-Y)=1/5,求(tanX)/(tanY)的值
已知sin(X+Y)=2/3,sin(X-Y)=1/5,求(tanX)/(tanY)的值
数学人气:274 ℃时间:2020-03-19 11:14:15
优质解答
(tanX)/(tanY)=(sinX/cosX)/(sinY/cosY)=(sinXcosY)/(cosXsinY)又sinXcosY=(1/2)[sin(X+Y)+sin(X-Y)]=(1/2)[(2/3)+(1/5)]=13/30cosXsinY=(1/2)[sin(X+Y)-sin(X-Y)]=(1/2)[(2/3)-(1/5)]=7/30代入原式,得(ta...
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