原式=(x²+3x+9)/(x-2)²*3(x-2)/(x-3)(x²+3x+9)*(x+3)(x-3)
=3/(x-2)(x-3)*(x+3)(x-3)
=3(x+3)/(x-2)
(x^2+3x+9/x^2-4x+4)/[(x-3)(x^2+3x+9)/3x-6)]/(1/x^2-9)
(x^2+3x+9/x^2-4x+4)/[(x-3)(x^2+3x+9)/3x-6)]/(1/x^2-9)
数学人气:659 ℃时间:2020-02-05 04:27:07
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