如图,⊙O切AC于E,切BC于F,切AB于G,连OE,OF,
∴OE⊥AC,OF⊥BC,
∴四边形CEOF为正方形,
∵∠C=90°,AC=6,BC=8,
∴AB=10,
设⊙O的半径为r,则CE=CF=r,
∴AE=AG=6-r,BF=BG=8-r,
∴AB=AG+BG=AE+BF,即6-r+8-r=10,
∴r=2.
故选B.
Rt△ABC中,∠C=90°,AC=6,BC=8,则△ABC的内切圆半径r=( ) A.1 B.2 C.3 D.5
Rt△ABC中,∠C=90°,AC=6,BC=8,则△ABC的内切圆半径r=( )
A. 1
B. 2
C. 3
D. 5
A. 1
B. 2
C. 3
D. 5
数学人气:873 ℃时间:2019-08-20 20:55:42
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