x2-3xy+2y2+x-2怎么因式分解
x2-3xy+2y2+x-2怎么因式分解
数学人气:944 ℃时间:2020-05-15 09:33:14
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这题要用待定系数法做因为 x²-3xy+2y²=(x-y)(x-2y)所以设 x²-3xy+2y²+x-2=(x-y+a)(x-2y+b)=x²-3xy+2y²+ax-2ay+bx-by+ab=x²-3xy+2y²+(a+b)x-(2a+b)y+ab比较系数,得a+b=1,-(2...
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