已知向量A=（2cosX,1）,向量B=（cosX,√3sin2X）（X∈R）,定义函数f（X）=向量A×向量B,若f（x）=1-√3,且x属于闭区间-π/3到π/3,则x=

f(x)=2cos²x+√3sin2X
=√3sin2X+cos2x+1
=2sin(2x+π/6)+1=1-√3
sin(2x+π/6)=-√3/2
x属于闭区间-π/3到π/3
2x+π/6属于闭区间-π/2到5π/6
所以 2x+π/6=-π/3
2x=-π/2
x=-π/4