x趋向0+时求lim(x^x-1)*lnx
x趋向0+时求lim(x^x-1)*lnx
数学人气：913 ℃时间：2020-03-21 12:34:10
优质解答
原式=[e^(xlnx)-1]*lnx.当x->0时,xlnx趋向于负无穷大（可用锣密达法则求出）所以原多项式分子趋向于0,分母趋向于负无穷大,总结果为0.
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