若3x^3m+5n+9 +9y^4m-2n+3=5是二元一次方程,则m除n等于

若3x^3m+5n+9 +9y^4m-2n+3=5是二元一次方程
3m+5n=1
4m-2n=1
解得m=7/26,n=-71/35
m除n=n/m=(-71/35)/(7/26)=-1846/245是3x^3m+5n+9不是3x^3m+5n是9y^4m-2n+3不是9y^4m-2n若3x^3m+5n+9 +9y^4m-2n+3=5是二元一次方程3m+5n+9=14m-2n+3=1解得m=-1，n=-1m除n=n/m=(-1)/(-1)=1