等判断下列函数的单调性,并求出单调区间(1)f(x)=x∧2+2x-4(2)f(x)=2x∧2-3x+3(3)f(x)=3x+x∧3

(1)f ' (x)=2x+2 令f ' (x)=0 得x=-1当x＞-1时,f ' (x)＞0,当x＜-1时,f ' (x)＜0 所以 减区间(-∞,-1),增区间(-1,+∞)(2)f ' (x)=4x-3 令f ' (x)=0,得x=3/4,当x＞3/4时,f ' (x)＞0,当x＜3/4时,f ' (x)＜0 所以减...