若向量a平行向量b,则等价有4cosα*4cosβ - sinα*sinβ = 0
等式除以cosα*cosβ得16-tanαtanβ=0
所以tanαtanβ=16.
以上步步可逆.得证
设a向量=(4cosα,sinα),向量b=(sinβ,4cosβ),若tanαtanβ=16,求证向量a平行向量b
设a向量=(4cosα,sinα),向量b=(sinβ,4cosβ),若tanαtanβ=16,求证向量a平行向量b
数学人气:504 ℃时间:2020-04-05 11:32:21
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