x=1/(√3-2)=-2-√3
y=1/(√3+2)=2-√3
x+y=-2√3
xy=-1
(x2+xy+y2)/(x+y)=[(x+y)²-xy]/(x+y)=11/(-2√3)=-11√3/6
x=1/(根号3-2),y=1/(根号3+2),求代数式(x2+xy+y2)/(x+y)的值
x=1/(根号3-2),y=1/(根号3+2),求代数式(x2+xy+y2)/(x+y)的值
数学人气:734 ℃时间:2019-09-29 01:35:45
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