2x²-6x+1=2(x²-3x)+1
=2(x-3/2)²-7/2
所以当x=3/2时有最小值,最小值为-7/2详细点2x²-6x+1=2(x²-3x)+1 =2[x²-2×3/2*x+(3/2)²-(3/2)²]+1 =2[(x-3/2)²-9/4]+1=2(x-3/2)²-9/2+1=2(x-3/2)²-7/2这是一个开口向上的二次函数,顶点为(3/2,-7/2)所以有最小值-7/2
当x= 时,代数式2x²-6x+1有最小值,这个值是
当x= 时,代数式2x²-6x+1有最小值,这个值是
数学人气:288 ℃时间:2019-10-31 11:51:25
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