∠AOD+∠BOC=360°-(∠BOC-∠AOD)=360°-90°-90°=180°,
又∵∠BOC-∠AOD=40°,
∴∠BOC=110°,∠AOD=70°.
如图,OA⊥OB,OC⊥OD,∠BOC-∠AOD=40°,求∠BOC与∠AOD的大小.
如图,OA⊥OB,OC⊥OD,∠BOC-∠AOD=40°,求∠BOC与∠AOD的大小.
数学人气:242 ℃时间:2019-10-08 04:49:15
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