4q（1-p)的三次方+2（p-1）平方 10（a-b）²-5（b-a）的三次方

4q（1-p)³+2（p-1）²
=4q(1-p)³+2(1-p)²
=2(1-p)²[2q(1-p)+1]
=2(1-p)²(2q-2pq+1)
10(a-b)²-5（b-a）³
=10(a-b)²+5(a-b)³
=5(a-b)²[2+(a-b)]
=5(a-b)²(a-b+2)