已知xy-x-y=11,求(xy-1)^2+(x+y-2)(x+y-2xy)的值.

xy-x-y=11,
x+y=xy-11
(xy-1)^2+(x+y-2)(x+y-2xy)
=(xy-1)^2+(xy-11-2)(xy-11-2xy)
=(xy)^2-2xy+1+(xy-13)(-xy-11)
=(xy)^2-2xy+1-(xy)^2-11xy+13xy+143
=144