式子中没有v哈!
已知(2s-u)分之(u-2s) = (s)分之(u-s),那么:
(2s-u)(u-s)=s(u-2s)
2su-u²-2s²+us=su-2s²
2su-u²=0
2su=u²
s=u/2题目写错啦是:(2s-u)分之(v-2s) =(s)分之(v-s)已知(2s-u)分之(v-2s) =(s)分之(v-s),那么:(2s-u)(v-s)=s(v-2s)2sv-uv-2s²+su=sv-2s²sv+su=uvs(v+u)=uvs=uv/(v+u)
已知(2s-u)分之(u-2s) = (s)分之(u-s) (u,v都是正整数,且u不等于v)则s=
已知(2s-u)分之(u-2s) = (s)分之(u-s) (u,v都是正整数,且u不等于v)则s=
是:(2s-u)分之(v-2s) =(s)分之(v-s)
(u,v都是正整数,且u不等于v)则s=
是:(2s-u)分之(v-2s) =(s)分之(v-s)
(u,v都是正整数,且u不等于v)则s=
数学人气:763 ℃时间:2020-02-05 01:53:54
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