若函数log2(ax^2-2x+2)>2在x∈【1,2】上恒成立,求实数a的取值范围

函数log2(ax^2-2x+2)>2在x∈【1,2】上恒成立∴ 函数log2(ax^2-2x+2)>log2(4)在x∈【1,2】上恒成立∵ y=log2(x)在（0,+∞）上是增函数∴ ax^2-2x+2>4在x∈【1,2】上恒成立即 ax²>2x+2在x∈【1,2】上恒成立即 a>2...