x/x-3=2+k/x-3
整理得
x/(x-3)-k/(x-3)=2
(x-k)/(x-3)=2
于是两边乘(x-3) ①
于是就得
x-k=2(x-3)
解得
x=6-k
要想无解只要使得①这一步等于0就是了
即把x=6-k代进(x-3) 使得
(x-3) =0
即
(6-k-3) =0
于是k=3的时候无解
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