计算：（x-3)分之1-（2x+6)分之1-（x的平方-6x+9)分之x
计算：（x-3)分之1-（2x+6)分之1-（x的平方-6x+9)分之x
数学人气：905 ℃时间：2020-01-27 05:07:52
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原式=1/(x-3)-1/2(x+3)-x/(x-3)²=[2(x+3)(x-3)-(x-3)²-2x(x+3)]/[2(x+3)(x-3)²]=(2x²-18-x²+6x-9-2x²+6x)/[2(x+3)(x-3)²]=(-x²+12x-27)/[2(x+3)(x-3)²]=-(x-3)(x-9)/[...
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