f(x)=x-(1/x²)
f'(x)=1+2/x^3中间过程能打一下吗啊,没有中间过程呀(x^n)'=nx^(n-1)(n≠0)1+2/x^3,这中间怎么变成+了,1/x²按着公式是1/2x为什么是2/x^3,谢谢-1/x^2=-x^(-2)所以求导后就变成[-x^(-2)]'=-(-2)x^(-2-1)=2/x^3
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