已知函数f(x)和g(x)的定义域为R,其中f(x)是奇函数,g(x)是偶函数,且f(x)+g(x)=1/(x的平方+x+1),则f(x)/g(x)的值域是?为什么?

f(x)是奇函数,g(x)是偶函数f(x)+g(x)=1/(x^2+x+1),则f(-x)+g(-x)=g(x)-f(x)=1/(x^2-x+1)相加2g(x)=2(x^2+1)/(x^2-x+1)(x^2+x+1)相减2f(x)=-2x/(x^2-x+1)(x^2+x+1)所以f(x)/g(x)=-x/(x^2+1)令a=-x/(x^2+1)ax^2+x+a=0...