解析
x=√2+1
y=√2-1
(x²-y²)/(x²+2xy+y²)
=(x-y)(x+y)/(x+y)²
=(x-y)/(x+y)
将x y代入
=(√2+1-√2+1)/(√2+1+√2-1)
=2/2√2
=√2/2
已知 x=根号2+1.y=根号2-1,试求x²+2xy+y²分之x²_y²的值,
已知 x=根号2+1.y=根号2-1,试求x²+2xy+y²分之x²_y²的值,
数学人气:876 ℃时间:2019-10-26 22:03:20
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