复变函数的一道题

(1+i)^i=((根号2)(cos(pi/4)+isin(pi/4))^i=(根号2)^i *(e^(i*pi/4))^i=(e^(ln(根号2)))^i *e^(-pi/4)=e^(i*(1/2)ln2)*e^(-pi/4)=(cos((ln2)/2)+i*sin((ln2)/2))*e^(-pi/4)=cos((ln2)/2)*e^(-pi/4) + i*sin((ln2)/2)...